MATH SOLVE

3 months ago

Q:
# What is the simplified form of 3 StartRoot 135 EndRoot?

Accepted Solution

A:

Answer:[tex]9 \sqrt{135}[/tex]Step-by-step explanation:Express 135 as a product of 15 and 9:[tex]135=15*9[/tex]So:[tex]3\sqrt{15*9}[/tex]Now, use the following property:[tex]\sqrt[n]{a*b} =\sqrt[n]{a}\hspace{3} \sqrt[n]{b}[/tex]Therefore:[tex]3\sqrt{15} \sqrt{9}[/tex]Since the square root of 9 is 3, the simplified form of [tex]3\sqrt{135}[/tex]:[tex]3\sqrt{15} \sqrt{9}=3*3\sqrt{15} =9\sqrt{15}[/tex]