Answer:[tex](q \circ r)(7)=22[/tex][tex](r \circ q)(7)=8[/tex]Step-by-step explanation:1st problem:[tex](q \circ r)(7)=q(r(7))[/tex]r(7) means to replace x in [tex]\sqrt{x+9}[/tex] with 7. [tex]r(7)=\sqrt{7+9}=\sqrt{16}=4[/tex] [tex](q \circ r)(7)=q(r(7))=q(4)[/tex]q(4) means replace x in [tex]x^2+6[/tex] with 4.[tex]q(4)=4^2+6=16+6=22[/tex].Therefore,[tex](q \circ r)(7)=q(r(7))=q(4)=22[/tex]2nd problem:[tex](r \circ q)(7)=r(q(7))[/tex]q(7) means replace x in [tex]x^2+6[/tex] with 7.[tex]q(7)=7^2+6=49+6=55[/tex].So now we have: [tex](r \circ q)(7)=r(q(7))=r(55)[/tex].r(55) means to replace x in [tex]\sqrt{x+9}[/tex] with 55. [tex]r(55)=\sqrt{55+9}=\sqrt{64}=8[/tex]Therefore, [tex](r \circ q)(7)=r(q(7))=r(55)=8[/tex].