MATH SOLVE

3 months ago

Q:
# he graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is graphed passing through the y-axis at y = 6. Function 2 y = 2x + 7 How much more is the rate of change of function 2 than the rate of change of function 1? 1 2 3 4

Accepted Solution

A:

Answer:The answer is 2Step-by-step explanation:Rate of change of function is given by :[tex]\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}[/tex]For function y = 6,rate of change = [tex]=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{6-6}{x_{2}-x_{1}}\\=0[/tex]because the function is independent of x.For function y = 2·x + 7,rate of change =[tex]=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}+7-2\cdot x_{1}-7}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}-2\cdot x_{1}}{x_{2}-x_{1}}\\=\frac{2\cdot (x_{2}-x_{1})}{x_{2}-x_{1}}\\=2[/tex]So, the rate of change of 2 is greater than rate of change of function 1 by 2 - 0 = 2.