Find the center, vertices, and foci of the ellipse with equationx^2/144+y^2/2525 = 1
Accepted Solution
A:
x^2/144+y^2/25=1
The largest denominator is a^2 and the smallest denominator is b^2, then: a^2=144→sqrt(a^2)=sqrt(144)→a=12 b^2=25→sqrt(b^2)=sqrt(25)→b=5
The equation is of the form: x^2/a^2+y^2/b^2=1 This is an ellipse with center C=(h,k) at the Origin → C=(0,0) and major axis on the x-axis and minor axis on the y-axis.
The vertices have coordinates: V'=(-a,0) and V=(a,0) Replacing a=12 V'=(-12,0) and V=(12,0)